2x^2+4x+10=4x+20

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Solution for 2x^2+4x+10=4x+20 equation: 


Simplifying
2x2 + 4x + 10 = 4x + 20

Reorder the terms:
10 + 4x + 2x2 = 4x + 20

Reorder the terms:
10 + 4x + 2x2 = 20 + 4x

Add '-4x' to each side of the equation.
10 + 4x + -4x + 2x2 = 20 + 4x + -4x

Combine like terms: 4x + -4x = 0
10 + 0 + 2x2 = 20 + 4x + -4x
10 + 2x2 = 20 + 4x + -4x

Combine like terms: 4x + -4x = 0
10 + 2x2 = 20 + 0
10 + 2x2 = 20

Solving
10 + 2x2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 2x2 = 20 + -10

Combine like terms: 10 + -10 = 0
0 + 2x2 = 20 + -10
2x2 = 20 + -10

Combine like terms: 20 + -10 = 10
2x2 = 10

Divide each side by '2'.
x2 = 5

Simplifying
x2 = 5

Take the square root of each side:
x = {-2.236067978, 2.236067978}

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